y=x^2-3/2x

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Solution for y=x^2-3/2x equation: 


x in (-oo:+oo)

y = x^2-((3/2)*x) // - x^2-((3/2)*x)

(3/2)*x-x^2+y = 0

3/2*x-x^2+y = 0

DELTA = (3/2)^2-(-1*4*y)

DELTA = 4*y+9/4

4*y+9/4 = 0

4*y+9/4 = 0 // - 9/4

4*y = -9/4 // : 4

y = -9/4/4

y = -9/16

DELTA = 0  <=>  t_1 = -9/16

x = -3/2/(-1*2) i y = -9/16

x = 3/4 i y = -9/16

( x = ((4*y+9/4)^(1/2)-3/2)/(-1*2) or x = (-(4*y+9/4)^(1/2)-3/2)/(-1*2) ) i y > -9/16

( x = ((4*y+9/4)^(1/2)-3/2)/(-2) or x = ((4*y+9/4)^(1/2)+3/2)/2 ) i y > -9/16

y+9/16 > 0

y+9/16 > 0 // - 9/16

y > -9/16

x in { 3/4, ((4*y+9/4)^(1/2)-3/2)/(-2), ((4*y+9/4)^(1/2)+3/2)/2 }

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